How to verify the second generation ID card number by using regular expression
Today, I will talk to you about how to use regular expressions to verify the second-generation ID card numbers, which may not be well understood by many people. in order to make you understand better, the editor has summarized the following contents for you. I hope you can get something according to this article.
IdCodeValid:function (code) {/ / ID card number legitimacy verification / / support 15-bit and 18-bit ID card number / / support address code, date of birth, check bit verification var city= {11: "Beijing", 12: "Tianjin", 13: "Hebei", 14: "Shanxi", 15: "Inner Mongolia", 21: "Liaoning", 22: "Jilin", 23: "Heilongjiang", 31: "Shanghai", 32: "Jiangsu" 33: "Zhejiang", 34: "Anhui", 35: "Fujian", 36: "Jiangxi", 37: "Shandong", 41: "Henan", 42: "Hubei", 43: "Hunan", 44: "Guangdong", 45: "Guangxi", 46: "Hainan", 50: "Chongqing", 51: "Sichuan", 52: "Guizhou", 53: "Yunnan", 54: "Xizang", 61: "Shaanxi", 62: Gansu " 63: Qinghai, 64: Ningxia, 65: Xinjiang, 71: Taiwan, 81: Hong Kong, 82: Macao, 91: abroad} Var row= {'pass':true,' msg':' Verification successful'}; if (! code | |! / ^\ d {6} (18 | 19 | 20)?\ d {2} (0 [1-9] | 1 [012]) (0 [1-9] | [12]\ d | 3 [01])\ d {3} (\ d | [xX]) $/ .test (code)) {row= {'pass':false,' msg':' ID number format error'} } else if (! city [code.substr (0Power2)]) {row= {'pass':false,' msg':' ID address coding error'};} else {/ / 18-bit ID card needs to verify the last check bit if (code.length = = 18) {code = code.split ('') / / ∑ (ai × Wi) (mod 11) / / weighting factor var factor = [7, 9, 10, 5, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2]; / / check bit var parity = [1, 0,'X-ray, 9, 8, 7, 6, 5, 4, 3, 2]; var sum = 0; var ai = 0; var wi = 0; for (var I = 0; I < 17) ISuppli +) {ai = code [I]; wi = factor [I]; sum + = ai * wi;} if (parity [sum% 11]! = code [17] .toUpperCase ()) {row= {'pass':false,' msg':' ID number check bit error'};} return row;} IdCodeValid ('xxx')
Regular expression:
Date of birth 1800-2099 (18 | 19 | 20)?\ d {2} (0 [1-9] | 1 [012]) (0 [1-9] | [12]\ d | 3 [01])
ID card regular expression / ^\ d {6} (18 | 19 | 20)?\ d {2} (0 [1-9] | 1 [012]) (0 [1-9] | [12]\ d | 3 [01])\ d {3} (\ d | [xX]) $/
Bit check rule 6-bit address code + 8-bit date of birth + 3-bit sequence number + 1-bit check bit
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