How to apply named parameters and optional parameters in C #

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I. brief introduction

The parameters of the design method are that some and all parameters can be assigned default values, and then when calling these methods, you can choose not to provide some arguments and use the default values defined by the parameters, in addition, you can also pass the arguments by specifying the parameter name when calling the method.

Code case class Program {private static int s = 0; private static int swatches = 0; private static void Mothed (int x = 9, string s = "A", DateTime dt= default (DateTime), Guid guid= new Guid ()) {Console.WriteLine ("x = {0}, s = {1}, dt= {2}, guid= {3}", x, s, dt, guid) } static void Main (string [] args) {Mothed (); / equivalent to Mothed (9, "A", default (Datetime), new Guid ()) Mothed (8, "X"); / / equivalent to Mothed (8, "X", default (Datetime), new Guid ()) Mothed (5, guid: Guid.NewGuid (), dt: DateTime.Now) / equivalent to Mothed (5, "A", DateTime.Now,Guid.NewGuid ()) Mothed (sroomnails, s_n++.ToString ()); / / equivalent to Mothed (0, "1", default (Datetime), new Guid ()); Mothed (s: (scoundrel +) .ToString (), x: sprinter +) / / is equivalent to the following two lines of code. Note that the order of the parameters here is independent of the order of the parameters, corresponding to / / string T1 = "2"; / / int32 t2quo3; / / Mothed (t2dint T1) default (Datetime), new Guid ()}}

When you pass arguments to a method, the compiler evaluates the arguments from left to right. In the fourth call to Mothed, the current default value of sroomn is 0, which is incremented and then equals 1 to string to s, and then continues to be incremented to 2 (sroomn _ increment + first used and then incremented) to x.

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