How does javascript judge odd and even numbers

This article will explain in detail how javascript judges odd and even numbers. The editor thinks it is very practical, so I share it with you as a reference. I hope you can get something after reading this article.

In JavaScript, you can use if statements, "%" and "= =" operators to determine whether a value can be divided by 2, and then to determine whether a value is odd or even. The syntax is "if (numeric% 2percent 0) {even code;} else {odd code;}".

The operating environment of this tutorial: windows10 system, javascript1.8.5 version, Dell G3 computer.

How to find odd and even numbers by javascript

In JavaScript, you can use if statements,% and = = operators to find odd and even numbers, as shown in the following example:

Document, click btn.onclick=function () {if (input1.value%2==0) {alert ("this is an even number");} else {alert ("this is an odd number");}

Output result:

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