How to implement nested list derivation by python

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Nested list derivation

[(I, j) for i in range (3) for j in range (I)] [(1,0), (2,0), (2,1)]

List derivation constructs permutation: can be implemented with itertools.permutations.

In [47]: a = 'abcd'In [48]: [i+j+k for i in a for j in a.replace (iMagnum') for k in a.replace (iMagne') Out [48]: ['abc',' abd', 'acb',' acd', 'adb',' bac', 'bad',' bca', 'bcd',' bda', 'bdc',' cab', 'cad' 'cba', 'cbd',' cda', 'cdb',' dab', 'dac',' dba', 'dbc',' dca', 'dcb'] Thank you for reading! This is the end of this article on "how to achieve nested list guidance in python". I hope the above content can be of some help to you, so that you can learn more knowledge. if you think the article is good, you can share it for more people to see!