Shulou(Shulou.com)06/01 Report--

1. Swap the contents of array A with the contents of array B. (the array is the same size)

Void swap (int * a, int * b)

{

Int ten = 0

Ten = * a

* a = * b

* b = ten

}

Int main ()

{

Int tem = 0

Int arr1 [4] = {1,2,3,4}

Int arr2 [4] = {5,6,7,8}

Int I = 0

For (I = 0; I)

< sizeof(arr1) / sizeof(arr1[0]);i++) { swap(&arr1[i], &arr2[i]); } for (i = 0; i < sizeof(arr1) / sizeof(arr1[0]); i++) printf("%d ", arr1[i]); printf("\n"); for (i = 0; i < sizeof(arr2) / sizeof(arr2[0]); i++) printf("%d ", arr2[i]); system("pause"); return 0; } 2.获取一个数二进制序列中所有的偶数位和奇数位，分别输出二进制序列。 #include #include #include #include void fun(int value) { int count = 0; int num = value; while (num) { count++; num = num >

> 1

}

While (count--)

{

Num = value

Num = value > > count

If (count% 2! = 0)

{

Printf ("even digit:")

Printf ("% d", num & 1)

}

Else

{

Printf ("Odd bits:")

Printf ("% d", num & 1)

}

Printf ("\ n")

}

}

Void ba (int value)

{

Int count = 0

Int num = value

While (num)

{

Count++

Num = num > > 1

}

While (count--)

{

Num = value

Num = value > > count

If ((num & 1) = = 1)

Printf ("% d", 1)

Else

Printf ("d", 0)

}

}

Int main ()

{

Int a = 10

Fun (a)

Ba (a)

System ("pause")

Return 0

}

3. Output the three numbers from large to small.

Void swap (int * a, int * b, int * c)

{

Int tem = 0

If (* a < * b)

{

Tem = * a

* a = * b

* b = tem

}

If (* a < * c)

{

Tem = * a

* a = * c

* c = * a

}

If (* b < * c)

{

Tem = * b

* b = * c

* c = tem

}

}

Int main ()

{

Int a = 10

Int b = 30

Int c = 5

Swap (& a, & b, & c)

Printf ("averse% d baked% d cased% d", a, b, c)

Getchar ()

Return 0

}

4. Find the greatest common divisor of two numbers.

Int main ()

{

Int a = 28

Int b = 24

Int count = 0

If (a% b = = 0)

Count = b

Else if (b% a = = 0)

Count = a

Else

{

Count = a% b

While (count! = 0)

{

A = b

B = count

Count = a% b

}

}

Printf ("% d", b)

System ("pause")

Return 0

}

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