Shulou(Shulou.com)06/01 Report--

This article will explain in detail how java solves the example problem of the immortal rabbit. The editor thinks it is very practical, so I share it with you as a reference. I hope you can get something after reading this article.

Immortal rabbit

Title:

There is a pair of rabbits that give birth to a pair of rabbits every month from the third month after birth, and the little rabbits give birth to another pair of rabbits every month after the third month. If the rabbits do not die, what is the number of rabbits in the twelfth month?

Analysis:

Define an array and initialize it dynamically, with a length of 20

The rabbit logarithms of the first month and the second month are both known, both being 1.

Calculate the rabbit logarithm of each month by loop

Outputs the value of the last element in the array (that is, the logarithm of the 20th month rabbit).

Practice:

The code is as follows (example):

Public class Demo4 {public static void main (String [] args) {/ / Don't like ginger, don't be jealous / / define an array and initialize it dynamically, the length is 20; int [] arr=new int [20]; / / the rabbit logarithms of the first month and the second month are known, both are 1 Arr [0] = arr [1] = 1; / / calculate the number of rabbit logarithms per month in a loop; for (int iTunes 2

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