How to use the math function of C++
Today, I would like to share with you the relevant knowledge points about how to use C++ 's math function. The content is detailed and the logic is clear. I believe most people still know too much about this knowledge, so share this article for your reference. I hope you can get something after reading this article.
Include header file
# include1, fabs (double x)
Take the absolute value of the variable of double type
# includeusing namespace std;#includeint main () {double dazzle color 3.14; printf ("% .2f\ n", fabs (d)); return 0;} 2, floor (double x) ceil (double x)
For a variable of double type, and the return type is also
Round down: floor
Round up: ceil
# includeusing namespace std;#includeint main () {double D1 colors 3.14; double d2 colors 3.14; printf ("% .0f% .0f\ n", floor (D1), ceil (D1)); printf (".0f% .0f\ n", floor (D2), ceil (D2)); return 0;}
-4-3
3 4
3. Pow (double xperfine double n)
Returns x to the nth power
# includeusing namespace std;#includeint main () {double d=pow (2.0 focus 3.0); printf ("% f\ n", d); return 0;}
8.000000
4. Sqrt (double x)
Returns the arithmetical square root of a variable of the multiplier type
# includeusing namespace std;#includeint main () {double d=sqrt (3.0); printf ("% f\ n", d); return 0;} 5, log (double x)
Returns the logarithm based on the natural logarithm e
# includeusing namespace std;#includeint main () {double d=log (exp (1)); / / exp (1) means e printf ("% f\ n", d); double d1=log10 (10.0); printf ("% f\ n", D1); double d2=log2 (2); printf ("% f\ n", D2); double d3=log1p (10); / / more precise printf ("% f\ n", D3); double d4=log (10) Printf ("% f\ n", d4); return 0;}
1.000000
1.000000
1.000000
2.397895
2.302585
6. Sin (double x) cos (double x) tan (double x)
The parameter requirement is Radian system.
There are also corresponding inverse functions.
# includeusing namespace std;#includeconst double PI=acos; / / because cos (pi) =-1int main () {double d=sin (PI/4); printf ("% f\ n", d); double d1=cos (PI/4); printf ("% f\ n", D1); double d2=tan (PI/4); printf ("% f\ n", D2); double d3=asin (1); printf ("% f\ n", D3) Double d4=atan (1); printf ("% f\ n", d4); return 0;} 7, round (double x)
Round the round variable, and return double.
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