How does php judge the day of the year according to the month and day of the year

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Judgment methods: 1, use "strtotime" statement to convert a given year, month and day into a timestamp format; 2, use "date (" z ", timestamp) + 1" statement to calculate the day of a year with a specified timestamp. The number of days returned by date () is calculated from 0, so the real number of days needs to be added by 1.

Operating environment of this tutorial: windows7 system, PHP7.1 version, DELL G3 computer

According to the year, month and day, php judges the day of the year.

In php, you can use the date () function to determine which day of the year a specified date is.

But the date () function handles timestamps, so you need to first use the strtotime () function to convert the year, month and day to the timestamp format.

The calculation syntax for the date () function:

Date ("z", timestamp)

The date () function is formatted with the character "z", and the date of the year can be calculated. Range of return values: from 0 to 365

Because the number of days returned is calculated from 0, the real number of days needs to be added by 1.

Implementation code:

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