How to use shell to calculate the total amount of downloads for each ip of access.log files

This article mainly introduces how to use shell to calculate the total amount of downloads of each ip in access.log files. The article is very detailed and has a certain reference value. Interested friends must finish reading it!

Working environment: Red Hat Enterprise Linux Server release 6.5 (Santiago), bash

#! / bin/bash

#

# cat xferlog | awk'{print $7J 8}'| sort-n | head-100 > ssh.txt

Cat xferlog | awk'{print $7 charge 8}'| sort-t. -k3pr 4-n > ssh.txt

Ip= (`cat ssh.txt | cut-d ""-f1`)

Dx= (`cat ssh.txt | cut-d ""-f2`)

Sum=0

For i in `seq 0 $((${# ip [@]}-1)) `

Do

# determine whether the read size is 0

If [${dx [$I]}! = 0]; then

Z1 = `echo "${dx [$I]} / 1024" | bc`

Sum=$ (($z1+$sum))

Fi

# judge whether it is in the end

If [$I! = ${# ip [@]}]; then

# determine whether the value is the second to last, and if so, compare it with the last one

If [$I = = $((${# ip [@]}-2))]; then

# if it is not equal, the value of the penultimate value and the last value are equal, then a sum is output

If [${ip [$((${# ip [@]}-1))]}! = ${ip [$((${# ip [@]}-2))]}]; then

[$num-ge 1024] & & echo "${ip [$I]}-$(($sum/1024)) M"

[${dx [$((${# dx [@]}-1))]}-ge 1024] & & echo "${ip [$(($item1))]}-$((${dx [$((${# dx [@]-1))]} / 1024)) M"

Exit 1

Else

Sum=$ (($sum+$ {dx [$((${# dx [@]}-1))]})

[$sum-ge 1024] & & echo "${ip [$I]}-$(($sum/1024)) M"

Exit 2

Fi

Else

# if you don't get to the second, make a normal comparison, and the latter one is compared with the current one

If [${ip [$(($iTun1))]}! = ${ip [$I]}]; then

[$sum-ge 1024] & & echo "${ip [$I]}-$(($sum/1024)) M"

Sum=0

Fi

Fi

Fi

Done

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