What are the common algorithm questions in JS interview
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1. Verify whether a number is a prime
1. If the number is 2 or 3, it must be prime
2. If it is an even number, it must not be a prime
3. If this number is not divisible by 3mure-any of its square roots, m must be a prime. And the divisor can be incremented each time (excluding even numbers)
Function isPrime (num) {
If (num = 2 | | num = 3) {
Return true
}
If (num% 2 = = 0) {
Return false
}
Let divisor = 3 limit = Math.sqrt (num)
While (limit > = divisor) {
If (num% divisor = = 0) {
Return false
}
Else {
Divisor + = 2
}
}
Return true
}
Console.log (isPrime (30)); / / false
two。 Fibonacci
The simplest thing to do: recursion.
Function fibonacci (n) {
If (n = divisor) {
If (a%divisor = 0 & & b%divisor = = 0) {
Res = divisor
}
Divisor++
}
Return res
}
Console.log (greatestCommonDivisor (8,4)); / / 4
Console.log (greatestCommonDivisor (69,169); / / 1
Solution 2:
Function greatestCommonDivisor (a _ r _ b) {
If (b = 0) {
Return a
} else {
Return greatestCommonDivisor (bmaine a% b)
}
}
4. Array deduplication
Traverse the original array
Get the value j of arr [I]
The value corresponding to the position j of the auxiliary array exits. If not, it is proved that the value of arr [I] is not duplicated.
At this point, the value j is stored in the res array, and the value of the auxiliary array j position is set to true.
Finally, the res array is returned.
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