How does Java implement a function so that the probability of return is the same
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Topic: give a function that returns 0 and 1, and the probability is p and 1. Please implement a function so that the probability of returning 01 is the same.
Idea: if you call the underlying random function twice in a row, there are four results:
1, 00 probability is pumped
2. The probability of 11 is (1m / p) * (1m / p)
The probability of 3 and 10 is (1m / p) * p
4. The probability of 01 is p * (1murp). It can be seen that the probability of result 3 and result 4 are equal.
Public class SameProbability {
/ * *
* the probability of generating 0 is p, and the probability of generating 1 is 1merp.
*
* the probability of generating 0 1 is p (1murp)
* the probability of generating 1 0 is (1murp) p
* is equal.
, /
Public static int getZeroOrOneSameProbability () {
Random ra = new Random ()
While (true) {
Int I = ra.nextInt (10)
Int j = ra.nextInt (10)
If (I = = 0 & j = = 1) {
Return 1
} else if (I = = 1 & & j = = 0) {
Return 0
} else {
Continue
}
}
}
Public static void main (String [] args) {
Int result = getZeroOrOneSameProbability ()
System.out.println (result)
}
}
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