How does javascript judge whether this year is a leap year?
This article mainly introduces "how to judge whether this year is a leap year by javascript". In daily operation, I believe many people have doubts about how to judge whether this year is a leap year by javascript. The editor has consulted all kinds of materials and sorted out simple and easy-to-use methods of operation. I hope it will be helpful to answer the doubts about "how to judge whether this year is a leap year by javascript". Next, please follow the editor to study!
Judgment method: 1, use the "new Date (). GetFullYear ()" statement to get the current year; 2, use the "year% 4 years 0 years & year 0 years 0 years" statement to determine whether the current year is a leap year, if you return true, it is a leap year, if you return false, it is not a leap year.
The operating environment of this tutorial: windows7 system, javascript1.8.5 version, Dell G3 computer.
Javascript judges whether this year is a leap year.
First we need to get the current year, using the Date object and getFullYear ().
Var myDate = new Date (); var Year = myDate.getFullYear (); / / abbreviation: var Year = new Date () .getFullYear ()
Then determine whether the obtained year is a leap year.
A year divisible by 4 but not divisible by 100 is a leap year.
Syntax:
Year% 4 years 0 years
If you return true, it is a leap year, and if you return false, it is not a leap year.
Add an if statement to select the output information.
If (4 years years 0 years years 0 years 0) {console.log (year+ "is a leap year");} else {console.log (year+ "not a leap year");}
OK, done!
Complete code:
Var year=new Date (). GetFullYear (); if (year4 years 0) {console.log (year+ "is a leap year");} else {console.log (year+ "not a leap year");}
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