How to use Linux shell script to get the IP address of public network

This article introduces the knowledge of "how to use Linux shell script to obtain public network IP address". In the operation of actual cases, many people will encounter such a dilemma, so let the editor lead you to learn how to deal with these situations. I hope you can read it carefully and be able to achieve something!

A shell script based on Linux system to obtain the IP address of public network. The content of the script is as follows: getIp.sh

#! / bin/bash# checks the legality of IP check_ipaddr () {echo $1 | grep "^ [0-9]\ {1pr 3\}\.\ ([0-9]\ {1pr 3\}\.\)\ {2\} [0-9]\ {1Med 3\} $" > / dev/null;if [$?-ne 0] then#echo "IP address must be all numeric" return 1fiipaddrature address 1a = `echo $ipaddr | awk-F. '{print $1}' `# to "." Separate and take out the value of each column b = `echo $ipaddr | awk-F. '{print $2}' `c = `echo $ipaddr | awk-F. '{print $3}' `d = `echo $ipaddr | awk-F. '{print $4}' `for num in $a $b $c $ddoif [$num-gt 255] | | [$num-lt 0] # each value must be in then#echo $ipaddr between 0-255. the field "$num" error "return 1fidone#echo $ipaddr" address is legal "return 0} host=ns1.dnspod.netport=16666ip= `cat / tcp/$host/$ port`check _ ipaddr" $ip "if [" $? "" x = "0" x]; thenecho "public network IP address: $ip" elseecho "failed to get IP address!" Fi

The output can be executed after authorizing the script with the command chmod + x getIp.sh.

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