How does python judge whether the elements in an and b are consistent?

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A = "abcd31d111111" b = "3acdb1"

There are a lot of answers to this question online, and the following code is just to throw a brick and attract jade.

Let me briefly say what I think here:

Analysis:

Judge whether the elements are the same, and judge whether the constituent elements are consistent, that is, the repeated elements can be calculated at once.

Method 1:

The way collections are used

A = "abcd31d111111" b = "3acdb1" print (set (a) = = set (b))

Method 2:

Use all ()

1. Judge the length first.

two。 Use python's all as a built-in method

A = "abcd31d111111" b = "3acdb1" long_ = an if len (a) > len (b) else bshort_ = an if len (a) < len (b) else bresult = all ([short_.count (x) for x in long_]) print (result) Thank you for your reading. This is the content of "how python judges whether the elements in an and b are consistent". After the study of this article I believe you have a deeper understanding of how python judges whether the elements in an and b are consistent, and the specific use needs to be verified in practice. Here is, the editor will push for you more related knowledge points of the article, welcome to follow!