The solution to the Parse error: syntax error, unexpected T_VAR error in PHP

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In fact, this is a very easy problem to solve. In my opinion, deja vu, hehe, recently I learned to use JavaScript to declare variables using var.

In fact, you don't need to use var declaration in PHP at all, but when a variable is a member of a class, there is no problem using var.

Use var externally to report an error Parse error: syntax error, unexpected T_VAR in..., such as my error message:

Parse error: syntax error, unexpected T_VAR in D:\ Apache2.2\ htdocs\ shirdrn\ page\ p2\ pageUtil.inc on line 34

I was testing: an error occurred when using a self-defined class object as a member of a class inside a class.

The address.inc code for the Address class:

The copy code is as follows:

The Person class and its test code are person.php as follows:

The copy code is as follows:

An exception occurred when the test failed:

Parse error: syntax error, unexpected T_VAR in D:\ Apache2.2\ htdocs\ shirdrn\ page\ p2\ pageUtil.inc on line 34

Just because you use var to declare variables in person.php code, you can't do this in PHP, as long as you start with a "$" symbol to indicate that the character is followed by a PHP variable.

Hehe: -)

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